Diketahui:
f(x) = 3x3 + 4x2 + 2
g(x) = x3 + 2x2 + 1
Ditanya:
y’ = f’(x) – g’(x)![]()
f(x) = 3x3 + 4x2 + 2
g(x) = x3 + 2x2 + 1
Ditanya:
y’ = f’(x) – g’(x)
Jawab:
y' = 6x² - 4x
y' = 2x (3x + 2)
Penjelasan dengan langkah-langkah:
f(x) = 3x³ + 4x² + 2
[tex]f'(x) = 3(3)x^{3-1} + 4(2)x^{2-1} + 2(0)\\f'(x) = 9x^2 + 8x[/tex]
g(x) = x³ + 2x² + 1
[tex]g'(x) = 1 (3) x^{3-1} + 2(2)x^{2-1} +1(0)\\g'(x) = 3x^2 +4x[/tex]
y' = f'(x) - g'(x)
y' = (9x² + 8x) - (3x² + 4x)
y' = (9x² - 3x²) - (8x - 4x)
y' = 6x² - 4x
y' = 2x (3x + 2)
[answer.2.content]
